EXERCISE 28 — AZIMUTH SUN Numerical Solutions

5. On 31^st August 2008, in DR 10˚ 11’ S 000˚ 00’, the azimuth of the sun was 282˚(C) when chron showed 05h 10m 25s. If the chron error was 00m 05s FAST and variation was 3˚E, find the deviation for the ship’s head.

GMT  31 Aug 17h 10m20s

GHA (31d 17h)            074˚  58.4’                Dec         N  08˚  19.6’
Incr. (10m 20s)           002˚  35.0’            d(-0.9)                  00.2’
GHA                              077˚  33.4’               Dec           N  08˚  19.4’
Long (E)                        000˚  00.0’
LHA                               077˚  33.4 ’          Lat                 10˚  11’ S

P = LHA
= 77˚  33.4’

We know  that :

Azimuth = N 79.4˚ W
T Az          = 280.6˚ (T)
C Az          = 282.0˚ (C)
Error         = 1.4˚W
Variation  =3.0˚ E
Deviation = 4.4˚ W