Chapter 12: Rising & Setting Of Celestial Bodies (Numericals Solution)

Solution: Given:- Weight = 8800t,Original KG =6.2m,Cargo loaded = 200t,KG = 1.7m Ship’s weight KG VM 8800 t 6.2m 54560tm (+) 200 load 1.7m Final VM  54900 tm Final W – 9000 t                                               Final VM  54900 tm So, we can calculate Final KG = (Final VM/ Final W)Final KG = (54900 / 9000)= 6.1m Here…

Solution :  Area of the flat keel plate = (10 x 2) = 20m2               Pressure = (depth x density) = (8 x 1.025) =  8.2t /m2                                 Thrust = (pressure x area)         …

Solution: Ship’s weight KG VM 2000t (load) 4.2m 3400 tm 300t (load) 2.0m (+) 600 tm 200t   (load) 3.2m (+) 640 tm 500t  (load ) 1.0 m (+)500 tm Final W   = 300t                                            …

Solution : Volume of rectangular log = (L x b x h)= (8m x 2m x 2m)= 32m3 Weight = (U/W volume ) x (Density of displaced water)Weight   = (8 x 2 x1.6) x(1)= 25. 6t RD = (mass / volume)= 25.6 / 32= 0.8t/m3 . Solution : Volume of rectangular log = (L x B…