Chapter 12: Rising & Setting Of Celestial Bodies (Numericals Solution)
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Solution: Given:- Weight = 8800t,Original KG =6.2m,Cargo loaded = 200t,KG = 1.7m Ship’s weight KG VM 8800 t 6.2m 54560tm (+) 200 load 1.7m Final VM 54900 tm Final W – 9000 t Final VM 54900 tm So, we can calculate Final KG = (Final VM/ Final W)Final KG = (54900 / 9000)= 6.1m Here…
NOTE: Also, we know that NOTES: Naming of Azimuth: The prefix N or S is the name same as C whereas suffix E or W depends on the value of LHA. If LHA is between 0 to 180, the body lies to the WEST and if it is between 180 and 360, the body lies to…
Solution : Area of the flat keel plate = (10 x 2) = 20m2 Pressure = (depth x density) = (8 x 1.025) = 8.2t /m2 Thrust = (pressure x area) …
Solution: Ship’s weight KG VM 2000t (load) 4.2m 3400 tm 300t (load) 2.0m (+) 600 tm 200t (load) 3.2m (+) 640 tm 500t (load ) 1.0 m (+)500 tm Final W = 300t …