# EXERCISE 28 — AZIMUTH SUN Numerical Solutions

**On 20th July 2008, AM at ship in DR 44˚ 31’ N 069˚ 42’ E, the azimuth of the sun was 100˚(C) when chron showed 04h 01m 52s. If the chron error was 04m 20s SLOW and variation was 8˚E, find the deviation for the ship’s head.**

**NOTE:**

- If LHA<180, P = LHA and If LHA>180, P = 360-LHA
- Naming of A, B, C: A is named opposite to the latitude when LHA is between 270 & 90 and same as latitude when LHA is between 90 & 270. B is named same as declination. For C, if A & B are of same names, add and retain names. If of contrary names then subtract and retain name of larger one.

Also, we know that

**NOTES:**

**Naming of Azimuth: The prefix N or S is the name same as C whereas suffix E or W depends on the value of LHA. If LHA is between 0 to 180, the body lies to the WEST and if it is between 180 and 360, the body lies to the EAST.**

**Azimuth =** S 76.9˚E**T Az= **103.1˚ (T)**C Az =** 100.0˚ (C)**Error =** 3.1˚ E**Variation =** 8.0˚ E**Deviation=** 4.9˚ W

**NOTE:**

**The calculation of deviation is elementary chartwork. It can be easily calculated by referring the following simple formulae: Error – Variation = Deviation**

**Where, if error & variation are of same names then subtract and retain name. If of contrary names, then add and retain the name of the larger one.**

For Question 2, Solution on Next page.