EXERCISE 28 — AZIMUTH SUN Numerical Solutions
3. On Jan 19th 2008, in DR 40˚ 16’S 175˚ 31’ E, the azimuth of the sun was 267˚(C) at 1618 ship’s time. If the ships time difference was 11h 30m from GMT and variation was 2.3˚E, find the deviation for the ship’s head.
d h m s
Ship’s time 19 16 18 00
Diff. (1130hr) (-)11 30 00
GMT 19 04 48 00
GMT 19THJan 04h 48m 00s
GHA (19d 04h) 237˚ 22.8’ Dec S 20˚ 28.4’
Incr. (48m 00s) 012˚ 00.0’ d(-0.5) 00.4’
GHA 249˚ 22.8’ Dec N 20˚ 28.0’
Long (E) (+)175˚ 31.0’
LHA 064˚ 53.8’ Lat 40˚ 16’ S
We know that:
P = LHA
= 064˚ 53.8’
![](https://indianmerchantnavy.org/wp-content/uploads/2023/01/image-9.png)
Azimuth = S 89.3˚W
T Az = 289.3˚ (T)
C Az = 287.0˚ (C)
Error = 2.3˚ E
Variation = 2.3˚ E
Deviation = NIL