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SOLUTION: Given : L =16m , B = 15m, H = 6m, RD=0.7 =16x15x6 = 1440m3 We know that : Density = Mass /Volume0.78 =Mass/1440m3 Hence, Mass =1123.2 tonnes SOLUTION: Given: Diameter = 8m, Radius = (d/2)m=(8/2)m =4mHeight =10mMass = 400tRD =0.9 We know that: Volume of the cylindrical tank = π2h= 3.1416 x 4…

### EXERCISE 28 — AZIMUTH SUN Numerical Solutions

NOTE: Also, we know that NOTES: Naming of Azimuth: The prefix N or S is the name same as C whereas suffix E or W depends on the value of LHA. If LHA is between 0 to 180, the body lies to the WEST and if it is between 180 and 360, the body lies to…

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Solutions of Principle of Navigation: Chapter 1: Earth (Numerical Solutions)

### Stability 1 – Chapter 6 Centre of Gravity

Solution: Given:- Weight = 8800t,Original KG =6.2m,Cargo loaded = 200t,KG = 1.7m Ship’s weight KG VM 8800 t 6.2m 54560tm (+) 200 load 1.7m Final VM 54900 tm Final W – 9000 t Final VM 54900 tm So, we can calculate Final KG = (Final VM/ Final W)Final KG = (54900 / 9000)= 6.1m Here…

### Stability I – Chapter 3 Flotation Solutions

Solution : Volume of rectangular log = (L x b x h)= (8m x 2m x 2m)= 32m3 Weight = (U/W volume ) x (Density of displaced water)Weight = (8 x 2 x1.6) x(1)= 25. 6t RD = (mass / volume)= 25.6 / 32= 0.8t/m3 . Solution : Volume of rectangular log = (L x B…