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Stability 1 – Chapter 6 Centre of Gravity
Solution: Given:- Weight = 8800t,Original KG =6.2m,Cargo loaded = 200t,KG = 1.7m Ship’s weight KG VM 8800 t 6.2m 54560tm (+) 200 load 1.7m Final VM 54900 tm Final W – 9000 t Final VM 54900 tm So, we can calculate Final KG = (Final VM/ Final W)Final KG = (54900 / 9000)= 6.1m Here…
Chapter 1: Earth (Numericals Solution)
Solutions of Principle of Navigation: Chapter 1: Earth (Numerical Solutions)
EXERCISE 28 — AZIMUTH SUN Numerical Solutions
NOTE: Also, we know that NOTES: Naming of Azimuth:Â Â The prefix N or S is the name same as C whereas suffix E or W depends on the value of LHA. If LHA is between 0 to 180, the body lies to the WEST and if it is between 180 and 360, the body lies to…
Stability 1 – Chapter 7 Final KG
Solution: Ship’s weight KG VM 2000t (load) 4.2m 3400 tm 300t (load) 2.0m (+) 600 tm 200t (load) 3.2m (+) 640 tm 500t (load ) 1.0 m (+)500 tm Final W = 300t …
Stability 1 Chapter 2 – Water Pressure
Solution :Â Â Area of the flat keel plate = (10 x 2) = 20m2Â Â Â Â Â Â Â Â Pressure = (depth x density) = (8 x 1.025) =Â 8.2t /m2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Thrust = (pressure x area)Â Â Â Â Â …