Chapter 12: Rising & Setting Of Celestial Bodies (Numericals Solution)

Solution : Volume of rectangular log = (L x b x h)= (8m x 2m x 2m)= 32m3 Weight = (U/W volume ) x (Density of displaced water)Weight   = (8 x 2 x1.6) x(1)= 25. 6t RD = (mass / volume)= 25.6 / 32= 0.8t/m3 . Solution : Volume of rectangular log = (L x B…

Solution: Ship’s weight KG VM 2000t (load) 4.2m 3400 tm 300t (load) 2.0m (+) 600 tm 200t   (load) 3.2m (+) 640 tm 500t  (load ) 1.0 m (+)500 tm Final W   = 300t                                            …

Solution: Given:- Weight = 8800t,Original KG =6.2m,Cargo loaded = 200t,KG = 1.7m Ship’s weight KG VM 8800 t 6.2m 54560tm (+) 200 load 1.7m Final VM  54900 tm Final W – 9000 t                                               Final VM  54900 tm So, we can calculate Final KG = (Final VM/ Final W)Final KG = (54900 / 9000)= 6.1m Here…

SOLUTION: Given : L =16m , B = 15m, H = 6m, RD=0.7 =16x15x6 = 1440m3 We know that : Density = Mass /Volume0.78 =Mass/1440m3 Hence, Mass =1123.2 tonnes SOLUTION: Given: Diameter = 8m, Radius = (d/2)m=(8/2)m =4mHeight =10mMass = 400tRD =0.9 We know that: Volume of the cylindrical tank = π2h= 3.1416 x 4…

Stability 1 – Chapter 5 Effect of Density Solutions > Exercise 5: Effect of density on draft and displacement – FWA ; DWA ; loadliness of ship. Solution: Displacement (W) = 16000 tTPC = 20 & SW draft = 8.0m We know that: Displacement when in SW = ( L X B x draft) x…