Stability Chapter 1 – Density and relative density Solutions.
Exact ullage where pump should be shut = (2.898 + 0.5)m
= 3.398m.
- A tank with a horizontal base and vertical sides is 10m deep and has rectangular trunkway 1m high. The volume of the tank alone is 8000m3 and that of the trunkway 500m3 . Find the ullage when 5320t of vegetable oil of RD 0.7 is loaded.
Given :
The depth of tank = 10m
Height of the trunkway = 1m
Volume of the tank alone =8000m3
Volume of the trunkway = 500m3
The mass of the oil =5320 t
RD =0.7
We know that,
Density = (mass /volume)
Volume = mass /density
= (5320 /0.7)
= 7600m3
Depth of oil = (volume /area)
= (7600/800)
=9.5m
Ullage insides the tank = (10 – 9.5)
=0.5m
Total ullage = (1 +0 .5)
= 1.5m.
- A rectangular tank has a total depth of 21m and volume of 20600 m3, which includes of trunkway of depth 1m and volume 600m3. find the ullage when 16320 t of oil of RD 0.8 is loaded.
Given :
The total depth of tank =21m
Volume of the tank = 20600m3
The height of the trunkway = 1m
Volume of the trunkway = 600m3
Oil loaded = 16320t
RD= 0.8
The height of the tank = (21-1)
= 20m
Volume of the tank= (20600 – 600)
=20000m3
Area of tank = (20000 /20)
=10000m2
Volume of the oil = (mass /density)
=(1620 /0.8)
= 20400 m3
Hence, Volume of the oil inside the trunkway = (Total volume of the oil – volume of the tank)
= (20400 – 20000)
=400m3
Depth of the oil = (volume /area)
= (400/600)
= 0.66m
Hence, Ullage = (1 -0.66)
= 0.33m
- A rectangular tank has a total depth of 10.5m and volume 8200m3, which include a trunkway of depth 0.5 m and volume 200m3 . find the mass of oil of oil of RD 0.8 loaded and the ullage, if 2% of the volume of the tank is left for expansion.
Given :
Depth of the tank is = 10.5m
Volume of the tank = 8200m3
Depth of the trunkway = 0.5m
Volume of the trunkway = 200m3
RD of the oil = 0.8
According to question, 2% of the tank volume left for expansion .
Volume of the tank alone = (8200-200)
= 8000m3
Height of the tank alone = (10.5 -0.5)
= 10 m
2% of the volume of the tank left for expansion .
= (2/100 x 8200)
=164m3
Volume of the oil to be load = (8200 -164)
=8036 m3
Mass of oil to be load = ( volume x density)
= (8036 x 0.8)
= 6428.8t
Volume of the trunkway = (L x B x 0.5)
= 200m3 ( given)
We can calculate Area as = (200 /0.5)
=400m2