Stability I – Chapter 3 Flotation Solutions

Solution: Ship’s weight KG VM 2000t (load) 4.2m 3400 tm 300t (load) 2.0m (+) 600 tm 200t   (load) 3.2m (+) 640 tm 500t  (load ) 1.0 m (+)500 tm Final W   = 300t                                            …

Solution : Given : – (L x B x H) of double bottom tank =( 20 x 10 .5 x 1)Cb = 0.82 , RD = 0.95 We know that: Cb   = (volume of tank) /( L x B x depth)0.82 = (volume of tank) /(20 x 10.5×1)volume of tank = 0.82 x ( 20…

Solution: RD of river = 1.010Summer load line on starboard side = 20mm abovePort side = 50mm above Mean draft = ( 20 + 50) / 2= (70/2)= 3.5cm above W = 15000t, FWA = (W/TPC)= 15000/(40 x 25)= 15cm As we know: Change in draft =  (Change in RD )x(FWA)         …

Solution : B = 14m, H =12m As we know that :Pressure = (depth x density)Thrust   = (pressure x area) An right angle triangle PBC , PB =7mSince, Height divide AB  equally into two parts.Triangle PBC  and   FEC are similarSo by law of similar angle triangle PB/ FE = PC / FC7 / FE  =12…