Stability I – Chapter 3 Flotation Solutions

Solution : Given : – (L x B x H) of double bottom tank =( 20 x 10 .5 x 1)Cb = 0.82 , RD = 0.95 We know that: Cb   = (volume of tank) /( L x B x depth)0.82 = (volume of tank) /(20 x 10.5×1)volume of tank = 0.82 x ( 20…

Solution : B = 14m, H =12m As we know that :Pressure = (depth x density)Thrust   = (pressure x area) An right angle triangle PBC , PB =7mSince, Height divide AB  equally into two parts.Triangle PBC  and   FEC are similarSo by law of similar angle triangle PB/ FE = PC / FC7 / FE  =12…

Exact ullage where pump should be shut = (2.898 + 0.5)m                                                                             = 3.398m. Given : The depth of…

Solution: Given:Weight = 12000t,Initial KG =7.6m,Cargo shifted = 300t,Change of KG = (8 – 2)= 6m downwards Derrick Height = 20m,KG of the Weight = 8m (since the weight is on the UD) Case – 1 Ship’s weight KG VM 12000 t      7.6m    91200tm 300t (shift)  12m  (+) 3600 tm Final W =12000…